Tensor

Results: 1074



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1TENSOR PRODUCT AND IRREGULARITY FOR HOLONOMIC D-MODULES by Jean-Baptiste Teyssier  Introduction

TENSOR PRODUCT AND IRREGULARITY FOR HOLONOMIC D-MODULES by Jean-Baptiste Teyssier Introduction

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Source URL: jbteyssier.com

Language: English - Date: 2015-01-28 14:51:41
2Lecture 3, Tues Jan 24: Basic Rules of QM Tensor products are a way of building bigger vectors out of smaller ones. Let’s apply a NOT operation to the first bit, and do nothing to the second bit. That’s really the sa

Lecture 3, Tues Jan 24: Basic Rules of QM Tensor products are a way of building bigger vectors out of smaller ones. Let’s apply a NOT operation to the first bit, and do nothing to the second bit. That’s really the sa

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Source URL: www.scottaaronson.com

Language: English - Date: 2018-08-29 13:55:03
3Incorporating Side Information in Tensor Completion Hemank Lamba*, Vaishnavh Nagarajan*, Kijung Shin*, Naji Shajarisales* Carnegie Mellon University 5000 Forbes Avenue Pittsburgh PA 15213, USA

Incorporating Side Information in Tensor Completion Hemank Lamba*, Vaishnavh Nagarajan*, Kijung Shin*, Naji Shajarisales* Carnegie Mellon University 5000 Forbes Avenue Pittsburgh PA 15213, USA

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Source URL: gdac.uqam.ca

Language: English - Date: 2017-10-04 00:47:55
4Tensority: an ASIC-friendly Proof of Work Algorithm Based on Tensor Bytom Foundation Email:  April 17, 2018 Abstract

Tensority: an ASIC-friendly Proof of Work Algorithm Based on Tensor Bytom Foundation Email: April 17, 2018 Abstract

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Source URL: bytom.io

Language: English - Date: 2018-04-18 21:58:58
5UNIVERSAL IDENTITIES, II: ⊗ AND ∧ KEITH CONRAD 1. Introduction We will describe how algebraic identities involving operations of multilinear algebra – the tensor product and exterior powers – can be proved by the

UNIVERSAL IDENTITIES, II: ⊗ AND ∧ KEITH CONRAD 1. Introduction We will describe how algebraic identities involving operations of multilinear algebra – the tensor product and exterior powers – can be proved by the

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Source URL: www.math.uconn.edu

Language: English - Date: 2017-08-15 21:37:35
    6Statistical Performance of Convex Tensor Decomposition Ryota Tomioka† Taiji Suzuki† Department of Mathematical Informatics, The University of Tokyo

    Statistical Performance of Convex Tensor Decomposition Ryota Tomioka† Taiji Suzuki† Department of Mathematical Informatics, The University of Tokyo

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    Source URL: tomioka.dk

    Language: English - Date: 2017-08-10 12:21:48
      7Extraction of Brain Cortical Activities Related to Auditory Impressions Induced by HVAC Sound Using Nonnegative Tensor Factorization

      Extraction of Brain Cortical Activities Related to Auditory Impressions Induced by HVAC Sound Using Nonnegative Tensor Factorization

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      Source URL: www.me.cs.scitec.kobe-u.ac.jp

      Language: English - Date: 2018-02-04 05:47:55
        8Tensor-Train Recurrent Neural Networks for Video Classification Yinchong Yang 1 2 Denis Krompass 2 Volker Tresp 1 2 arXiv:1707.01786v1 [cs.CV] 6 JulAbstract

        Tensor-Train Recurrent Neural Networks for Video Classification Yinchong Yang 1 2 Denis Krompass 2 Volker Tresp 1 2 arXiv:1707.01786v1 [cs.CV] 6 JulAbstract

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        Source URL: www.dbs.ifi.lmu.de

        Language: English - Date: 2017-07-14 22:42:06
          9Convex Tensor Decomposition via Structured Schatten Norm Regularization Ryota Tomioka Toyota Technological Institute at Chicago Chicago, IL 60637

          Convex Tensor Decomposition via Structured Schatten Norm Regularization Ryota Tomioka Toyota Technological Institute at Chicago Chicago, IL 60637

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          Source URL: tomioka.dk

          Language: English - Date: 2017-08-10 12:21:48
            10Tensor products  Let R be a commutative ring. Given R-modules M1 , M2 and N we say that a map b: M1 × M2 → N is R-bilinear if for all r, r0 ∈ R and module elements mi , m0i ∈ Mi we have b(r · m1 + r0 · m01 , m2

            Tensor products Let R be a commutative ring. Given R-modules M1 , M2 and N we say that a map b: M1 × M2 → N is R-bilinear if for all r, r0 ∈ R and module elements mi , m0i ∈ Mi we have b(r · m1 + r0 · m01 , m2

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            Source URL: www.math.ru.nl

            Language: English - Date: 2018-03-17 15:08:06