Cryptography module, AnswersInitially, we have L0 = 86, R0 = 83, K0 = 89. Then we run the first round, to obtain L1 = 83, R1 = 2. Also, K1 = 164. So, computing the next round, we have L2 = 9 and R2 = 2. So the out - K1 - Document - PDFSEARCH.IO

First Page	Meta Content
	Cryptography module, AnswersInitially, we have L0 = 86, R0 = 83, K0 = 89. Then we run the first round, to obtain L1 = 83, R1 = 2. Also, K1 = 164. So, computing the next round, we have L2 = 9 and R2 = 2. So the out Add to Reading List Document Date: 2017-11-13 11:53:55 Open Document File Size: 100,02 KB Share Result on Facebook

Cryptography module, AnswersInitially, we have L0 = 86, R0 = 83, K0 = 89. Then we run the first round, to obtain L1 = 83, R1 = 2. Also, K1 = 164. So, computing the next round, we have L2 = 9 and R2 = 2. So the outAdd to Reading List