Cryptography module, AnswersInitially, we have L0 = 86, R0 = 83, K0 = 89. Then we run the first round, to obtain L1 = 83, R1 = 2. Also, K1 = 164. So, computing the next round, we have L2 = 9 and R2 = 2. So the out

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Date: 2017-11-13 11:53:55		Cryptography module, AnswersInitially, we have L0 = 86, R0 = 83, K0 = 89. Then we run the first round, to obtain L1 = 83, R1 = 2. Also, K1 = 164. So, computing the next round, we have L2 = 9 and R2 = 2. So the out Add to Reading List Source URL: www.cs.bham.ac.uk Download Document from Source Website File Size: 100,02 KB Share Document on Facebook